4(x+1)^2+28=40

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Solution for 4(x+1)^2+28=40 equation: 



4(x+1)^2+28=40

We move all terms to the left:

4(x+1)^2+28-(40)=0

We add all the numbers together, and all the variables

4(x+1)^2-12=0

We move all terms containing x to the left, all other terms to the right

4(x+1)^2=12

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